VSA2 marksYear: 2025EasyCBSE Class 10
trianglessimilaritycorresponding-sides
Question
If △ABC∼△PQR in which AB=6 cm, BC=4 cm, AC=8 cm and PR=6 cm, then find the length of (PQ+QR).
Solution
1
Since △ABC∼△PQR: PQAB=QRBC=PRAC, i.e., PQ6=QR4=68
+0.5 marks2
PQ=86×6=29=4.5 cm and QR=84×6=3 cm
+1 mark3
∴PQ+QR=4.5+3=7.5 cm
+0.5 marks