Assertion (A): $ABCD$ is a trapezium with $DC \parallel AB$. $E$ and $F$ are points on $AD$ and $BC$ respectively, such that $EF \parallel AB$. Then $\frac{AE}{ED} = \frac{BF}{FC}$.

Reason (R): Any l

Question

Assertion (A): $ABCD$ is a trapezium with $DC \parallel AB$. $E$ and $F$ are points on $AD$ and $BC$ respectively, such that $EF \parallel AB$. Then $\frac{AE}{ED} = \frac{BF}{FC}$.

Reason (R): Any line parallel to parallel sides of a trapezium divides the non-parallel sides proportionally.

Accepted Answer

Step 1: Both Assertion and Reason are true. The reason (BPT applied to trapezium) correctly explains why $EF \parallel AB$ implies proportional division of non-parallel sides.

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Solution