In the given figure, $DE \parallel BC$. If $AD = 2$ units, $DB = 3$ units and $AE = 3$ units and $EC = x$ units, then the value of $x$ is:

[IMAGE_1]

(a) $2$
(b) $3$
(c) $5$
(d) $\frac{9}{2}$

Question

In the given figure, $DE \parallel BC$. If $AD = 2$ units, $DB = 3$ units and $AE = 3$ units and $EC = x$ units, then the value of $x$ is:

[IMAGE_1]

(a) $2$
(b) $3$
(c) $5$
(d) $\frac{9}{2}$

Accepted Answer

Step 1: By BPT: $\frac{AD}{DB} = \frac{AE}{EC} \Rightarrow \frac{2}{3} = \frac{3}{x} \Rightarrow x = \frac{9}{2}$

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