VSA2 marksYear: 2023MediumCBSE Class 10
trianglessimilarityBPTparallel-lines
Question
In the given figure, XZ is parallel to BC. AZ=3 cm, ZC=2 cm, BM=3 cm and MC=5 cm. Find the length of XY.

Solution
1
As XZ∥BC, therefore XBAX=23=ZCAZ ... (i)
+0.5 marks3
⇒ABAX=BMXY or 53=3XY
+0.5 marks4
⇒XY=59 or 1.8 cm
+0.5 marks