In Figure 1, $ABC$ is an isosceles triangle, right-angled at $C$. Therefore

[IMAGE_1]

Question

In Figure 1, $ABC$ is an isosceles triangle, right-angled at $C$. Therefore

[IMAGE_1]

Accepted Answer

Step 1: Since $	riangle ABC$ is isosceles and right-angled at $C$, we have $AC = BC$. By Pythagoras theorem: $AB^2 = AC^2 + BC^2 = AC^2 + AC^2 = 2AC^2$

Question

Solution