A bucket open at the top has top and bottom radii of circular ends as 40 cm and 20 cm respectively. Find the volume of the bucket if its depth is 21 cm. Also find the area of the tin sheet required fo

Question

A bucket open at the top has top and bottom radii of circular ends as 40 cm and 20 cm respectively. Find the volume of the bucket if its depth is 21 cm. Also find the area of the tin sheet required for making the bucket. (Use $\pi = \frac{22}{7}$)

Accepted Answer

Step 1: Volume $= \frac{\pi h}{3}[R^2 + r^2 + Rr] = \frac{22}{7} 	imes \frac{21}{3}[40^2 + 20^2 + 40 	imes 20]$
Step 2: $= 61600$ cm$^3$
Step 3: $l = \sqrt{h^2 + (R - r)^2} = \sqrt{21^2 + 20^2} = 29$ cm. Area of tin $= \pi(R + r)l + \pi r^2 = \pi[29 	imes 60 + 400]$
Step 4: $= 6725.7$ cm$^2$

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