500 persons are taking dip into a cuboidal pond which is 80 m long and 50 m broad. What is the rise of water level in the pond, if the average displacement of the water by a person is 0.04 m$^3$?

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Step 1: Let the rise in water level be $h$. $500 	imes 0.04 = 80 	imes 50 	imes h$
Step 2: $\Rightarrow h = \frac{20}{80 	imes 50} = 0.005$ m

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