LA4 marksYear: 2020HardCBSE Class 10
statisticsmediancumulative-frequency
Question
The median of the following data is 525. Find the values of x and y, if total frequency is 100.
| Class | 0-100 | 100-200 | 200-300 | 300-400 | 400-500 | 500-600 | 600-700 | 700-800 | 800-900 | 900-1000 |
|---|---|---|---|---|---|---|---|---|---|---|
| Frequency | 2 | 5 | x | 12 | 17 | 20 | y | 9 | 7 | 4 |
Solution
1
| Classes | Frequency | Cumulative Frequency |
|---|---|---|
| 0-100 | 2 | 2 |
| 100-200 | 5 | 7 |
| 200-300 | x | 7+x |
| 300-400 | 12 | 19+x |
| 400-500 | 17 | 36+x |
| 500-600 | 20 | 56+x |
| 600-700 | y | 56+x+y |
| 700-800 | 9 | 65+x+y |
| 800-900 | 7 | 72+x+y |
| 900-1000 | 4 | 76+x+y |
+2 marks2
76+x+y=100⇒x+y=24 ... (i)
500−600 is the median class.
Median =500+2050−(36+x)×100=525
+1 mark3
Solving we get, x=9.
From (i), y=15.
+1 mark