Find the length of the shadow on the ground of a pole of height $18$ m when angle of elevation $ heta$ of the sun is such that $ an heta = \frac{6}{7}$.

Question

Find the length of the shadow on the ground of a pole of height $18$ m when angle of elevation $	heta$ of the sun is such that $	an 	heta = \frac{6}{7}$.

Accepted Answer

Step 1: Let $AP$ be the length of shadow. In $	riangle APB$, $	an 	heta = \frac{AB}{AP} = \frac{18}{AP}$.
Step 2: $\frac{6}{7} = \frac{18}{AP} \Rightarrow AP = \frac{18 	imes 7}{6} = 21$ m.

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