Kite festival is celebrated in many countries at different times of the year. In India, every year 14th January is celebrated as International Kite Day. On this day many people visit India and participate in the festival by flying various kinds of kites.
The picture given below, shows three kites flying together.
In Fig. 5, the angles of elevation of two kites (Points A and B) from the hands of a man (Point C) are found to be 30° and 60° respectively. Taking AD=50 m and BE=60 m, find
(1) the lengths of strings used (take them straight) for kites A and B as shown in the figure.
(2) the distance 'd' between these two kites.
Solution
1
(1) sin60°=23=BC60⇒BC=403 m
+1 mark
2
sin30°=21=AC50⇒AC=100 m
+1 mark
3
(2) Since DE is a straight line, ∠ACB=90°. d2=AC2+BC2=(100)2+(403)2=10000+4800=14800
+1.5 marks
4
d=14800=2037 m
+0.5 marks
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