If $ ext{HCF}(98, 28) = m$ and $ ext{LCM}(98, 28) = n$, then the value of $n - 7m$ is:

Question

If $	ext{HCF}(98, 28) = m$ and $	ext{LCM}(98, 28) = n$, then the value of $n - 7m$ is:

Accepted Answer

Step 1: $	ext{HCF}(98, 28) = 14$, so $m = 14$. $	ext{LCM}(98, 28) = \frac{98 	imes 28}{14} = 196$, so $n = 196$. Therefore $n - 7m = 196 - 98 = 98$.

Question