In a $2$-digit number, the digit at the unit's place is $5$ less than the digit at the ten's place. The product of the digits is $36$. Find the number.

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Accepted Answer

Step 1: Let digit at ten's place be $x$, then digit at unit's place $= x - 5$
Step 2: $x(x - 5) = 36 \Rightarrow x^2 - 5x - 36 = 0$
Step 3: $(x - 9)(x + 4) = 0$
Step 4: $x = 9$ (rejecting $x = -4$)
Step 5: Required number is $94$

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