Solve the quadratic equation: $x^2 + 2\sqrt{2}x - 6 = 0$ for $x$.

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Accepted Answer

Step 1: $D = (2\sqrt{2})^2 - 4(1)(-6) = 8 + 24 = 32$
Step 2: $x = \frac{-2\sqrt{2} \pm \sqrt{32}}{2} = \frac{-2\sqrt{2} \pm 4\sqrt{2}}{2}$
Step 3: $x = \sqrt{2}$ or $x = -3\sqrt{2}$

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Solution