Three coins are tossed simultaneously. What is the probability of getting
(i) at least one head?
(ii) exactly two tails?
(iii) at most one tail?

Question

Accepted Answer

Step 1: Total number of outcomes $= 8$. (i) $P(	ext{at least one head}) = \frac{7}{8}$
Step 2: (ii) $P(	ext{exactly 2 tails}) = \frac{3}{8}$
Step 3: (iii) $P(	ext{at most one tail}) = \frac{4}{8} = \frac{1}{2}$

Question

Solution