Find the probability that a leap year selected at random will contain 53 Sundays and 53 Mondays.

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Accepted Answer

Step 1: 366 days $= 52$ weeks $+ 2$ days. Total possible outcomes are 7: (SM, MT, TW, WTh, ThF, FS, SS)
Step 2: Favourable outcome (53 Sundays and 53 Mondays) $= 1$ (Sunday, Monday). $P = \frac{1}{7}$

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