If '$\alpha$' and '$\beta$' are the zeroes of the polynomial $p(y) = y^2 - 5y + 3$, then find the value of $\alpha^4\beta^3 + \alpha^3\beta^4$.

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Step 1: $\alpha + \beta = 5$, $\alpha\beta = 3$.
$\alpha^4\beta^3 + \alpha^3\beta^4 = (\alpha\beta)^3(\alpha + \beta)$
Step 2: $= 3^3 	imes 5 = 27 	imes 5 = 135$

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