Zeroes of the polynomial $p(x) = x^2 - 3\sqrt{2}x + 4$ are:

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Step 1: $x^2 - 3\sqrt{2}x + 4 = 0$. $x = \frac{3\sqrt{2} \pm \sqrt{18 - 16}}{2} = \frac{3\sqrt{2} \pm \sqrt{2}}{2}$. $x = \frac{4\sqrt{2}}{2} = 2\sqrt{2}$ or $x = \frac{2\sqrt{2}}{2} = \sqrt{2}$.

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