$3$ chairs and $1$ table cost \u20b9 $900$; whereas $5$ chairs and $3$ tables cost \u20b9 $2,100$. If the cost of $1$ chair is \u20b9 $x$ and the cost of $1$ table is \u20b9 $y$, then the situation ca

Question

$3$ chairs and $1$ table cost \u20b9 $900$; whereas $5$ chairs and $3$ tables cost \u20b9 $2,100$. If the cost of $1$ chair is \u20b9 $x$ and the cost of $1$ table is \u20b9 $y$, then the situation can be represented algebraically as

Accepted Answer

Step 1: $3$ chairs $+ 1$ table $= 900 \Rightarrow 3x + y = 900$. $5$ chairs $+ 3$ tables $= 2100 \Rightarrow 5x + 3y = 2100$.

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