If $ an A = \sqrt{3}$, where $A$ is an acute angle, then find the value of $\frac{1}{1 + \cos A}$.

Question

If $	an A = \sqrt{3}$, where $A$ is an acute angle, then find the value of $\frac{1}{1 + \cos A}$.

Accepted Answer

Step 1: $	an A = \sqrt{3} \Rightarrow A = 60°$
Step 2: $\frac{1}{1 + \cos A} = \frac{1}{1 + \cos 60°} = \frac{1}{1 + \frac{1}{2}} = \frac{1}{\frac{3}{2}} = \frac{2}{3}$

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