If $\sin heta = \cos heta$, $(0°

Question

If $\sin 	heta = \cos 	heta$, $(0° < 	heta < 90°)$, then value of $(\sec 	heta \cdot \sin 	heta)$ is:

Accepted Answer

Step 1: $\sin 	heta = \cos 	heta \Rightarrow 	heta = 45°$. So $\sec 45° \cdot \sin 45° = \sqrt{2} 	imes \frac{1}{\sqrt{2}} = 1$

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