**Assertion (A):** If $\sin A = \frac{1}{3}$, $(0°

Question

**Assertion (A):** If $\sin A = \frac{1}{3}$, $(0° < A < 90°)$, then the value of $\cos A$ is $\frac{2\sqrt{2}}{3}$.

**Reason (R):** For every angle $	heta$, $\sin^2 	heta + \cos^2 	heta = 1$.

Accepted Answer

Step 1: $\cos A = \sqrt{1 - \sin^2 A} = \sqrt{1 - \frac{1}{9}} = \sqrt{\frac{8}{9}} = \frac{2\sqrt{2}}{3}$. Both A and R are true, and R is the correct explanation of A.

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