If $\sec heta - an heta = m$, then the value of $\sec heta + an heta$ is:

Question

If $\sec	heta - 	an	heta = m$, then the value of $\sec	heta + 	an	heta$ is:

Accepted Answer

Step 1: Using identity $\sec^2	heta - 	an^2	heta = 1$:
$(\sec	heta - 	an	heta)(\sec	heta + 	an	heta) = 1$
$m(\sec	heta + 	an	heta) = 1 \Rightarrow \sec	heta + 	an	heta = \frac{1}{m}$

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