If $A = 60°$ and $B = 30°$, verify that:
$\sin(A + B) = \sin A \cos B + \cos A \sin B$

Question

Accepted Answer

Step 1: LHS $= \sin(60° + 30°) = \sin 90° = 1$
Step 2: RHS $= \sin 60° \cos 30° + \cos 60° \sin 30°$
$= \frac{\sqrt{3}}{2} 	imes \frac{\sqrt{3}}{2} + \frac{1}{2} 	imes \frac{1}{2} = \frac{3}{4} + \frac{1}{4} = 1$
$	herefore$ LHS $=$ RHS

Question

Solution