$\left[\frac{3}{4} an^2 30° - \sec^2 45° + \sin^2 60° ight]$ is equal to
(A) $-1$
(B) $\frac{5}{6}$
(C) $\frac{-3}{6}$
(D) $\frac{1}{6}$

Question

$\left[\frac{3}{4} 	an^2 30° - \sec^2 45° + \sin^2 60°ight]$ is equal to
(A) $-1$
(B) $\frac{5}{6}$
(C) $\frac{-3}{6}$
(D) $\frac{1}{6}$

Accepted Answer

Step 1: (A) $-1$

Question