If $ an heta = \sqrt{3}$, find the value of $\left(\frac{2 \sec heta}{1 + an^2 heta} ight)$.

Question

If $	an 	heta = \sqrt{3}$, find the value of $\left(\frac{2 \sec 	heta}{1 + 	an^2 	heta}ight)$.

Accepted Answer

Step 1: $\sec^2 	heta = 1 + 3 = 4$. $	herefore \sec 	heta = 2$
Step 2: Hence $\frac{2 \sec 	heta}{1 + 	an^2 	heta} = \frac{2 	imes 2}{4} = 1$

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