Introduction To Trigonometry
> Question
VSA
1 mark
Year: 2020
Easy
CBSE Class 10
trigonometry
complementary-angles
Question
t
a
n
50°
3
c
o
t
40°
−
2
1
⋅
s
i
n
55°
c
o
s
35°
=
________.
Solution
1
cot
40°
=
tan
50°
and
cos
35°
=
sin
55°
. So
t
a
n
50°
3
×
t
a
n
50°
−
2
1
×
s
i
n
55°
s
i
n
55°
=
3
−
2
1
=
2
5
+1 mark
Practice this question interactively with step-by-step AI feedback
Sign up for SuperPadhai