Show that $ an^4 heta + an^2 heta = \sec^4 heta - \sec^2 heta$.

Question

Show that $	an^4 	heta + 	an^2 	heta = \sec^4 	heta - \sec^2 	heta$.

Accepted Answer

Step 1: L.H.S $= 	an^4 	heta + 	an^2 	heta = 	an^2 	heta(	an^2 	heta + 1)$
Step 2: $= (\sec^2 	heta - 1)(\sec^2 	heta) = \sec^4 	heta - \sec^2 	heta = $ R.H.S

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