P$(x, y)$, Q$(-2, -3)$ and R$(2, 3)$ are the vertices of a right triangle PQR right angled at P. Find the relationship between $x$ and $y$. Hence, find all possible values of $x$ for which $y = 2$.

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Step 1: In $	riangle PQR$, $\angle P = 90°$.
$PQ^2 + PR^2 = QR^2$
$(x+2)^2 + (y+3)^2 + (x-2)^2 + (y-3)^2 = 4^2 + 6^2$
Step 2: $x^2 + y^2 = 13$
Step 3: For $y = 2$: $x^2 = 9 \Rightarrow x = \pm 3$.

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