$A(3, 0)$, $B(6, 4)$ and $C(-1, 3)$ are vertices of a triangle $ABC$. Find length of its median $BE$.

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Step 1: Mid-point of $AC$ is $E\left(\frac{3 + (-1)}{2}, \frac{0 + 3}{2}\right) = E\left(1, \frac{3}{2}\right)$
Step 2: Length of median $BE = \sqrt{(6 - 1)^2 + \left(4 - \frac{3}{2}\right)^2} = \sqrt{25 + \frac{25}{4}} = \sqrt{\frac{125}{4}} = \frac{5\sqrt{5}}{2}$

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