Find the type of triangle $ABC$ formed whose vertices are $A(1, 0)$, $B(-5, 0)$ and $C(-2, 5)$.

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Accepted Answer

Step 1: $AB = \sqrt{(-5-1)^2 + (0-0)^2} = 6$
Step 2: $BC = \sqrt{(-5+2)^2 + (0-5)^2} = \sqrt{34}$
Step 3: $CA = \sqrt{(1+2)^2 + (0-5)^2} = \sqrt{34}$
Step 4: $BC = CA$, so $	riangle ABC$ is isosceles.

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