$AD$ is a median of $ riangle ABC$ with vertices $A(5, -6)$, $B(6, 4)$ and $C(0, 0)$. Length $AD$ is equal to:

Question

$AD$ is a median of $	riangle ABC$ with vertices $A(5, -6)$, $B(6, 4)$ and $C(0, 0)$. Length $AD$ is equal to:

Accepted Answer

Step 1: Midpoint of $BC$: $D = \left(\frac{6+0}{2}, \frac{4+0}{2}\right) = (3, 2)$
$AD = \sqrt{(5-3)^2 + (-6-2)^2} = \sqrt{4 + 64} = \sqrt{68}$

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