If Q(0, 1) is equidistant from P(5, -3) and R(x, 6), find the values of x.... | SA 3m | Maths | SuperPadhai

Coordinate Geometry > Question

SA3 marksYear: 2023EasyCBSE Class 10

coordinate-geometrydistance-formulaequidistant

Question

If

Q (0, 1)

is equidistant from

P (5, - 3)

and

R (x, 6)

, find the values of

x

.

Solution

1

PQ = QR \Rightarrow P Q^{2} = Q R^{2}

(5 - 0)^{2} + (- 3 - 1)^{2} = (x - 0)^{2} + (6 - 1)^{2}

+1 mark

2

\Rightarrow 25 + 16 = x^{2} + 25 \Rightarrow x^{2} = 16

+1 mark

3

\Rightarrow x = 4, x = - 4

+1 mark

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