If $(-5, 3)$ and $(5, 3)$ are two vertices of an equilateral triangle, then find coordinates of the third vertex, given that origin lies inside the triangle. (Take $\sqrt{3} = 1.7$)

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Step 1: Let the third vertex be $(x, y)$.
$A(-5, 3)$, $B(5, 3)$, $C(x, y)$
$AB = 10$, $AC$:
$AC^2 = (-5 - x)^2 + (3 - y)^2 = (5 - x)^2 + (3 - y)^2$
$20x = 0$
$x = 0$
Step 2: $(3 - y)^2 = 75$
$3 - y = \pm 5\sqrt{3}$
$y = 3 - 5\sqrt{3}$
Step 3: $y = -5.5$
The coordinates of the third vertex are $(0, -5.5)$

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