Find the area of a quadrilateral $ABCD$ having vertices at $A(1, 2)$, $B(1, 0)$, $C(4, 0)$ and $D(4, 4)$.

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Question

Find the area of a quadrilateral $ABCD$ having vertices at $A(1, 2)$, $B(1, 0)$, $C(4, 0)$ and $D(4, 4)$.

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Accepted Answer

Step 1: ar$(	riangle ABC) = \frac{1}{2}|1(0 - 0) + 1(0 - 2) + 4(2 - 0)| = 3$ sq. units
Step 2: ar$(	riangle ACD) = \frac{1}{2}|1(0 - 4) + 4(4 - 2) + 4(2 - 0)| = 6$ sq. units. $	herefore$ Area of quadrilateral $= 3 + 6 = 9$ sq. units

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