SA3 marksYear: 2020EasyCBSE Class 10
coordinate-geometryarea-of-triangle
Question
Find the area of triangle PQR formed by the points P(−5,7), Q(−4,−5) and R(4,5).
Solution
1
ar(PQR)=21∣x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣
=21∣−5(−5−5)+(−4)(5−7)+4(7+5)∣
+1 mark2
=21∣50+8+48∣=21×106
+1 mark