Prove that the tangents drawn at the ends of a diameter of a circle are parallel.

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Step 1: Tangents $l$ and $m$ are drawn at the end points A and B of the diameter AB of the circle.
$\angle 1 = 90°$, $\angle 2 = 90°$ (tangent is perpendicular to radius at point of contact).
Step 2: $	herefore \angle 1 = \angle 2$. But these are alternate interior angles.
$	herefore l \parallel m$.

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