MCQ1 markYear: 2025MediumCBSE Class 10
circlestangentangle-in-semicirclealternate-segment-theorem
Question
In the given figure, RS is the tangent to the circle at the point L and MN is the diameter. If ∠NML=30°, then ∠RLM is:

Solution
1
∠MLN=90° (angle in semicircle). ∠MNL=180°−90°−30°=60°. ∠RLM=∠MNL=60° (angle between tangent and chord equals angle in alternate segment).
+1 mark