At point A on the diameter AB of a circle of radius 10 cm, tangent XAY is drawn to the circle. Find the length of the chord CD parallel to XY at a distance of 16 cm from A.

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Step 1: $AP = 16$ cm. $	herefore OP = 16 - 10 = 6$ cm. $XY \parallel CD$, $	herefore \angle CPO = 90°$.
Step 2: In right $	riangle OPC$, $CP = \sqrt{(10)^2 - (6)^2} = \sqrt{100 - 36} = \sqrt{64} = 8$ cm
Step 3: $CD = 2 	imes CP = 2 	imes 8 = 16$ cm

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