A person is standing at P outside a circular ground at a distance of 26 m from the centre of the ground. He found that his distances from the points A and B on the ground are 10 m (PA and PB are tangents to the circle). Find the radius of the circular ground.
Solution
1
∠OAP=90° (radius ⊥ tangent). In right △OAP:
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2
(26)2=OA2+(10)2⇒676=OA2+100⇒OA2=576
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3
OA=576=24 m. ∴ Radius =24 m.
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