In the given figure, PA is a tangent from an external point P to a circle with centre O. If $\angle POB = 115°$, then $\angle APO$ is equal to:

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Question

In the given figure, PA is a tangent from an external point P to a circle with centre O. If $\angle POB = 115°$, then $\angle APO$ is equal to:

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Accepted Answer

Step 1: Since PA is a tangent, $\angle OAP = 90°$. $\angle AOP = 180° - 115° = 65°$. In $	riangle OAP$: $\angle APO = 180° - 90° - 65° = 25°$.

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