A chord of a circle of radius 10 cm subtends a right angle at its centre. The length of the chord (in cm) is:

[IMAGE_1]

Question

A chord of a circle of radius 10 cm subtends a right angle at its centre. The length of the chord (in cm) is:

[IMAGE_1]

Accepted Answer

Step 1: Using Pythagoras: $AB^2 = OA^2 + OB^2 = 10^2 + 10^2 = 200 \Rightarrow AB = 10\sqrt{2}$ cm

Question