MCQ1 markYear: 2024EasyCBSE Class 10
circlestangentscommon-tangent
Question
In the given figure, QR is a common tangent to the two given circles touching externally at A. The tangent at A meets QR at P. If AP=4.2 cm, then the length of QR is:

Solution
1
PQ=PA=4.2 cm and PR=PA=4.2 cm (tangents from external point P). QR=PQ+PR=8.4 cm
+1 mark