In the given figure, tangents $PA$ and $PB$ to the circle centred at $O$, from point $P$ are perpendicular to each other. If $PA = 5$ cm, then length of $AB$ is equal to

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In the given figure, tangents $PA$ and $PB$ to the circle centred at $O$, from point $P$ are perpendicular to each other. If $PA = 5$ cm, then length of $AB$ is equal to

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Accepted Answer

Step 1: $PA = PB = 5$ cm (tangents from external point). $\angle APB = 90°$. $OAPB$ is a square. $AB = \sqrt{PA^2 + PB^2} = \sqrt{25 + 25} = 5\sqrt{2}$ cm

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