VSA2 marksYear: 2023MediumCBSE Class 10
circlestangentsecantangle
Question
In the given figure, PA is a tangent to the circle drawn from the external point P and PBC is the secant to the circle with BC as diameter. If ∠AOC=130°, then find the measure of ∠APB, where O is the centre of the circle.
Solution
1
∠AOB=180°−130°=50° (since BOC is a diameter, ∠AOB+∠AOC=180°). ∠OAP=90° (radius ⊥ tangent).
+1 mark2
∠APB=180°−(50°+90°)=40°.
+1 mark