In the given figure, $AC$ and $AB$ are tangents to a circle centered at $O$. If $\angle COD = 120°$, then $\angle BAO$ is equal to:

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In the given figure, $AC$ and $AB$ are tangents to a circle centered at $O$. If $\angle COD = 120°$, then $\angle BAO$ is equal to:

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Accepted Answer

Step 1: Since $AC$ and $AB$ are tangents from $A$, $\angle BOD = 360° - 120° - 90° - 90° = 60°$ (using $\angle OCA = \angle OBA = 90°$). By symmetry, $\angle BAO = \frac{1}{2}(180° - 120°) = 30°$.

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