In the given figure, $AB$ is a tangent to the circle centered at $O$. If $OA = 6$ cm and $\angle OAB = 30°$, then the radius of the circle is:

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Question

In the given figure, $AB$ is a tangent to the circle centered at $O$. If $OA = 6$ cm and $\angle OAB = 30°$, then the radius of the circle is:

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Accepted Answer

Step 1: In $	riangle OAB$, $\sin 30° = \frac{OB}{OA} \Rightarrow \frac{1}{2} = \frac{r}{6} \Rightarrow r = 3$ cm

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