In the given figure, PQ is a tangent to the circle with centre O. If $\angle OPQ = x$, $\angle POQ = y$, then $x + y$ is:

[IMAGE_1]

Question

In the given figure, PQ is a tangent to the circle with centre O. If $\angle OPQ = x$, $\angle POQ = y$, then $x + y$ is:

[IMAGE_1]

Accepted Answer

Step 1: Since PQ is a tangent at Q, $\angle OQP = 90°$. In $	riangle OPQ$: $x + y + 90° = 180° \Rightarrow x + y = 90°$

Question