VSA2 marksYear: 2020MediumCBSE Class 10
circlestangentperimetertriangle
Question
In Figure 7, find the perimeter of △ABC, if AP=12 cm.

Solution
1
AP=AB+BP=AB+BD (tangents from B)
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AQ=AC+CQ=AC+CD (tangents from C)
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⇒AP+AQ=AB+BD+AC+CD=AB+AC+BC. But AP=AQ (tangents from A), so 2AP= Perimeter of △ABC.
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Perimeter =2×12=24 cm
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