The 10^{th} term of the AP 5, \frac{19}{4}, \frac{9}{2}, \frac{17}{4}, \ldots is:... | MCQ 1m | Maths | SuperPadhai

Arithmetic Progressions > Question

MCQ1 markYear: 2025EasyCBSE Class 10

arithmetic-progressionsnth-term

Question

The

1 0^{t h}

term of the AP

5, \frac{19}{4}, \frac{9}{2}, \frac{17}{4}, \dots

is:

Solution

1

a = 5 = \frac{20}{4}

,

d = \frac{19}{4} - \frac{20}{4} = - \frac{1}{4}

.

a_{10} = a + 9 d = \frac{20}{4} + 9 \times (- \frac{1}{4}) = \frac{20 - 9}{4} = \frac{11}{4}

.

+1 mark

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