Arithmetic Progressions
> Question
SA
3 marks
Year: 2020
Medium
CBSE Class 10
arithmetic-progressions
sum
equation
Question
Solve the equation:
1
+
4
+
7
+
10
+
…
+
x
=
287
.
Solution
1
Let sum of
n
terms
=
287
.
2
n
[
2
×
1
+
(
n
−
1
)
3
]
=
287
+0.5 marks
2
3
n
2
−
n
−
574
=
0
+0.5 marks
3
(
3
n
+
41
)
(
n
−
14
)
=
0
.
n
=
14
(Reject
n
=
3
−
41
)
+1 mark
4
x
=
a
14
=
1
+
13
×
3
=
40
+1 mark
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